hitunglah setiap integral berikut ( 3ײ-6×+1)
Penjelasan dengan langkah-langkah:
[tex]\int\limits^ {}(3x^2-6x+1) \, dx[/tex]
= [tex]\int\limits^ {}3x^2 \, dx - \int\limits^ {}6x \, dx + \int\limits^ {}1 \, dx[/tex]
(Rumus integral : [tex]\frac{1}{n + 1}x^{n+1}[/tex])
= [tex]3(\frac{x}{2+1}x^{2+1}) - 6(\frac{1}{1+1}x^{1+1}) + (\frac{1}{0+1}x^{0+1}) + C[/tex]
= [tex]\frac{3x^3}{3} - \frac{6x^2}{2} + x + C[/tex]
= [tex]x^3 - 3x^2 + x + C[/tex]